notify/grove: set the service to "ansible" by default

reviewable/pr18780/r1
zimbatm 11 years ago
parent 58573e37c7
commit 9848d27f9f

@ -16,8 +16,9 @@ options:
required: true required: true
service: service:
description: description:
- Name of the service (displayed in the message) - Name of the service (displayed as the "user" in the message)
required: true required: false
default: ansible
message: message:
description: description:
- Message content - Message content
@ -66,7 +67,7 @@ def main():
argument_spec = dict( argument_spec = dict(
channel_token = dict(type='str', required=True), channel_token = dict(type='str', required=True),
message = dict(type='str', required=True), message = dict(type='str', required=True),
service = dict(type='str', required=True), service = dict(type='str', default='ansible'),
url = dict(type='str', default=None), url = dict(type='str', default=None),
icon_url = dict(type='str', default=None), icon_url = dict(type='str', default=None),
) )

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