openssl_csr: fix SAN handling for cryptography backend (#53927)

* Fix IP address support for openssl_csr.

* Remove DirName support, which doesn't work as this and seems harder to fix. Also, I don't know of an example of how it actually works.
pull/53935/head
Felix Fontein 6 years ago committed by ansibot
parent 29d6418822
commit 96925a09b6

@ -353,6 +353,7 @@ try:
import cryptography.hazmat.backends
import cryptography.hazmat.primitives.serialization
import cryptography.hazmat.primitives.hashes
import ipaddress
CRYPTOGRAPHY_VERSION = LooseVersion(cryptography.__version__)
except ImportError:
CRYPTOGRAPHY_IMP_ERR = traceback.format_exc()
@ -673,16 +674,17 @@ class CertificateSigningRequestCryptography(CertificateSigningRequestBase):
raise CertificateSigningRequestError('Unknown subject field identifier "{0}"'.format(id))
def _get_san(self, name):
if name.startswith('DNS:'):
return cryptography.x509.DNSName(to_text(name[4:]))
if name.startswith('IP:'):
return cryptography.x509.IPAddress(to_text(name[3:]))
if name.startswith('email:'):
return cryptography.x509.RFC822Name(to_text(name[6:]))
if name.startswith('URI:'):
return cryptography.x509.UniformResourceIdentifier(to_text(name[4:]))
if name.startswith('DirName:'):
return cryptography.x509.DirectoryName(to_text(name[8:]))
try:
if name.startswith('DNS:'):
return cryptography.x509.DNSName(to_text(name[4:]))
if name.startswith('IP:'):
return cryptography.x509.IPAddress(ipaddress.ip_address(to_text(name[3:])))
if name.startswith('email:'):
return cryptography.x509.RFC822Name(to_text(name[6:]))
if name.startswith('URI:'):
return cryptography.x509.UniformResourceIdentifier(to_text(name[4:]))
except Exception as e:
raise CertificateSigningRequestError('Cannot parse Subject Alternative Name "{0}": {1}'.format(name, e))
if ':' not in name:
raise CertificateSigningRequestError('Cannot parse Subject Alternative Name "{0}" (forgot "DNS:" prefix?)'.format(name))
raise CertificateSigningRequestError('Cannot parse Subject Alternative Name "{0}" (potentially unsupported by cryptography backend)'.format(name))

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