require pycurl for linode module

reviewable/pr18780/r1
Jon Chen 11 years ago
parent 71e4d76da9
commit 798b4bdf1b

@ -88,7 +88,7 @@ options:
description: description:
- how long before wait gives up, in seconds - how long before wait gives up, in seconds
default: 300 default: 300
requirements: [ "linode-python" ] requirements: [ "linode-python", "pycurl" ]
author: Vincent Viallet author: Vincent Viallet
notes: notes:
- LINODE_API_KEY env variable can be used instead - LINODE_API_KEY env variable can be used instead
@ -156,14 +156,19 @@ import time
import os import os
try: try:
# linode module raise warning due to ssl - silently ignore them ... import pycurl
import warnings except ImportError:
warnings.simplefilter("ignore") print("failed=True msg='pycurl required for this module'")
sys.exit(1)
try:
from linode import api as linode_api from linode import api as linode_api
except ImportError: except ImportError:
print("failed=True msg='linode-python required for this module'") print("failed=True msg='linode-python required for this module'")
sys.exit(1) sys.exit(1)
def randompass(): def randompass():
''' '''
Generate a long random password that comply to Linode requirements Generate a long random password that comply to Linode requirements

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