Changed when new sysctl file is created

When destination sysctl file is missing, it is created.
But, for idempotency purposes, the creation process now takes place just before it is used, in the
main code path so an empty file is not left over if the code
module.fail_jsons before the file is really used.
reviewable/pr18780/r1
Michel Blanc 12 years ago
parent aea822c47a
commit 05d45fc1fa

@ -155,17 +155,6 @@ def sysctl_check(current_step, **sysctl_args):
if not os.access(sysctl_args['key_path'], os.R_OK): if not os.access(sysctl_args['key_path'], os.R_OK):
return 1, 'key_path is not a readable file, key seems to be uncheckable' return 1, 'key_path is not a readable file, key seems to be uncheckable'
# sysctl file exists and openable ?
# TODO choose if prefered to use os.access() instead try/catch on open
if current_step == 'before':
if not os.access(sysctl_args['sysctl_file'], os.W_OK):
try:
f = open(sysctl_args['sysctl_file'],'w')
f.write('')
f.close()
except IOError, e:
return 1, 'unable to create supplied sysctl file (directory missing)'
# no smart checks at this step ? # no smart checks at this step ?
if sysctl_args['checks'] == 'none': if sysctl_args['checks'] == 'none':
return 0, '' return 0, ''
@ -246,6 +235,14 @@ def main():
if res != 0: if res != 0:
module.fail_json(msg='checks_before failed with: ' + msg) module.fail_json(msg='checks_before failed with: ' + msg)
if not os.access(sysctl_args['sysctl_file'], os.W_OK):
try:
f = open(sysctl_args['sysctl_file'],'w')
f.write('')
f.close()
except IOError, e:
module.fail_json(msg='unable to create supplied sysctl file (destination directory probably missing)')
# reading the file # reading the file
for line in open(sysctl_args['sysctl_file'], 'r').readlines(): for line in open(sysctl_args['sysctl_file'], 'r').readlines():
if not line.strip(): if not line.strip():

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