getFeedName: return empty string instead of null when element is not found

master
Andrew Dolgov 14 years ago
parent 6c70137c73
commit b71a7df9ed

@ -874,13 +874,15 @@ function resort_category(node, cat_mode) {
var by_unread = feedsSortByUnread();
var list = node.getElementsByTagName("LI");
for (i = 0; i < list.length; i++) {
for (j = i+1; j < list.length; j++) {
var tmp_val = get_feed_entry_unread(list[i]);
var cur_val = get_feed_entry_unread(list[j]);
//console.log(list[i].id + " vs " + list[j].id);
var tmp_name = get_feed_entry_name(list[i]).toLowerCase();
var cur_name = get_feed_entry_name(list[j]).toLowerCase();
@ -999,7 +1001,7 @@ function getFeedName(id, is_cat) {
if (e) {
return e.innerHTML.stripTags();
} else {
return null;
return '';
}
}

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