don't allow duplicate feeds for user

master
Andrew Dolgov 19 years ago
parent f72dbbdefc
commit 7e9a398637

@ -949,17 +949,31 @@
if (!WEB_DEMO_MODE) {
$feed_link = db_escape_string($_GET["link"]);
$result = db_query($link,
"INSERT INTO ttrss_feeds (owner_uid,feed_url,title) VALUES ('".$_SESSION["uid"]."', '$feed_link', '')");
$result = db_query($link,
"SELECT id FROM ttrss_feeds WHERE feed_url = '$feed_link' AND owner_uid = " . $_SESSION["uid"]);
"SELECT id FROM ttrss_feeds
WHERE feed_url = '$feed_link' AND owner_uid = ".$_SESSION["uid"]);
if (db_num_rows($result) == 0) {
$result = db_query($link,
"INSERT INTO ttrss_feeds (owner_uid,feed_url,title)
VALUES ('".$_SESSION["uid"]."', '$feed_link', '')");
$feed_id = db_fetch_result($result, 0, "id");
$result = db_query($link,
"SELECT id FROM ttrss_feeds WHERE feed_url = '$feed_link'
AND owner_uid = " . $_SESSION["uid"]);
$feed_id = db_fetch_result($result, 0, "id");
if ($feed_id) {
update_rss_feed($link, $feed_link, $feed_id);
}
} else {
if ($feed_id) {
update_rss_feed($link, $feed_link, $feed_id);
print "<div class=\"warning\">
Feed <b>$feed_link</b> already exists in the database.
</div>";
}
}
}

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