Improve handling of $ref in swagger files

It turns out that swagger merges $refed attributes with those defined inline,
so do the same here.
pull/977/head
Richard van der Hoff 9 years ago
parent 4c46c95d0e
commit 262c9ea113

@ -36,15 +36,19 @@ logger = logging.getLogger(__name__)
def resolve_references(path, schema):
if isinstance(schema, dict):
result = {}
# do $ref first
if '$ref' in schema:
value = schema['$ref']
path = os.path.join(os.path.dirname(path), value)
with open(path) as f:
ref = yaml.load(f)
result = resolve_references(path, ref)
del schema['$ref']
else:
result = {}
for key, value in schema.items():
if key == "$ref":
path = os.path.join(os.path.dirname(path), value)
with open(path) as f:
schema = yaml.load(f)
return resolve_references(path, schema)
else:
result[key] = resolve_references(path, value)
result[key] = resolve_references(path, value)
return result
elif isinstance(schema, list):
return [resolve_references(path, value) for value in schema]
@ -342,7 +346,7 @@ class MatrixUnits(Units):
# have either "x-example" or a "schema" with an "example".
params_missing_examples = [
p for p in single_api.get("parameters", []) if (
"x-example" not in p and
"x-example" not in p and
not Units.prop(p, "schema/example")
)
]
@ -600,7 +604,7 @@ class MatrixUnits(Units):
# {
# title: "<title> key"
# rows: [
# { key: <key_name>, type: <string>,
# { key: <key_name>, type: <string>,
# desc: <desc>, required: <bool> }
# ]
# }

Loading…
Cancel
Save