Commit Graph

16 Commits (6567e05cbc3c2b685274d755d5aa274e66c40e4a)

Author SHA1 Message Date
Matt Clay 3033fd96b0
Move unit test compat code out of `lib/ansible/`. (#46996)
* Move ansible.compat.tests to test/units/compat/.
* Fix unit test references to ansible.compat.tests.
* Move builtins compat to separate file.
* Fix classification of test/units/compat/ dir.
6 years ago
Matt Clay a11f631ee4 Python 3.8 collections compatibility fixes.
Includes a new pylint blacklist plugin to prevent regressions.
6 years ago
Michael Vermaes fad3a4dc83 Fix typo in vault decrypt error message (#31335) 7 years ago
Adrian Likins 934b645191 Support multiple vault passwords (#22756)
Fixes #13243

** Add --vault-id to name/identify multiple vault passwords

Use --vault-id to indicate id and path/type

 --vault-id=prompt  # prompt for default vault id password
 --vault-id=myorg@prompt  # prompt for a vault_id named 'myorg'
 --vault-id=a_password_file  # load ./a_password_file for default id
 --vault-id=myorg@a_password_file # load file for 'myorg' vault id

vault_id's are created implicitly for existing --vault-password-file
and --ask-vault-pass options.

Vault ids are just for UX purposes and bookkeeping. Only the vault
payload and the password bytestring is needed to decrypt a
vault blob.

Replace passing password around everywhere with
a VaultSecrets object.

If we specify a vault_id, mention that in password prompts

Specifying multiple -vault-password-files will
now try each until one works

** Rev vault format in a backwards compatible way

The 1.2 vault format adds the vault_id to the header line
of the vault text. This is backwards compatible with older
versions of ansible. Old versions will just ignore it and
treat it as the default (and only) vault id.

Note: only 2.4+ supports multiple vault passwords, so while
earlier ansible versions can read the vault-1.2 format, it
does not make them magically support multiple vault passwords.

use 1.1 format for 'default' vault_id

Vaulted items that need to include a vault_id will be
written in 1.2 format.

If we set a new DEFAULT_VAULT_IDENTITY, then the default will
use version 1.2

vault will only use a vault_id if one is specified. So if none
is specified and C.DEFAULT_VAULT_IDENTITY is 'default'
we use the old format.

** Changes/refactors needed to implement multiple vault passwords

raise exceptions on decrypt fail, check vault id early

split out parsing the vault plaintext envelope (with the
sha/original plaintext) to _split_plaintext_envelope()

some cli fixups for specifying multiple paths in
the unfrack_paths optparse callback

fix py3 dict.keys() 'dict_keys object is not indexable' error

pluralize cli.options.vault_password_file -> vault_password_files
pluralize cli.options.new_vault_password_file -> new_vault_password_files
pluralize cli.options.vault_id -> cli.options.vault_ids

** Add a config option (vault_id_match) to force vault id matching.

With 'vault_id_match=True' and an ansible
vault that provides a vault_id, then decryption will require
that a matching vault_id is required. (via
--vault-id=my_vault_id@password_file, for ex).

In other words, if the config option is true, then only
the vault secrets with matching vault ids are candidates for
decrypting a vault. If option is false (the default), then
all of the provided vault secrets will be selected.

If a user doesn't want all vault secrets to be tried to
decrypt any vault content, they can enable this option.

Note: The vault id used for the match is not encrypted or
cryptographically signed. It is just a label/id/nickname used
for referencing a specific vault secret.
7 years ago
Abhijeet Kasurde b89cb95609 Fix spelling mistakes (comments only) (#25564)
Original Author : klemens <ka7@github.com>

Taking over previous PR as per
https://github.com/ansible/ansible/pull/23644#issuecomment-307334525

Signed-off-by: Abhijeet Kasurde <akasurde@redhat.com>
8 years ago
Dag Wieers 4efec414e7 test/: PEP8 compliancy (#24803)
* test/: PEP8 compliancy

- Make PEP8 compliant

* Python3 chokes on casting int to bytes (#24952)

But if we tell the formatter that the var is a number, it works
8 years ago
Toshio Kuratomi 2fff690caa Update module_utils.six to latest (#22855)
* Update module_utils.six to latest

We've been held back on the version of six we could use on the module
side to 1.4.x because of python-2.4 compatibility.  Now that our minimum
is Python-2.6, we can update to the latest version of six in
module_utils and get rid of the second copy in lib/ansible/compat.
8 years ago
Matt Martz 87aa59af79 Legacy pep8 updates for setup.py and tests 8 years ago
Brian Coca a2c38c47aa added docs for vault and made trigger shorter: !vault (#20985)
* added docs for vault and made trigger shorter: !vault

* added single var valuting

* Update playbooks_vault.rst

Edit pass for spelling and grammar. Ship it!

* Update playbooks_vault.rst

Typo fixes.
8 years ago
Adrian Likins 51e3ef89a9 Add error info if tabs are found in the yaml (#18343)
If a yaml file fails to load because of tabs being used
for formatting, detect that and show a error message
with more details.
8 years ago
Toshio Kuratomi 4ed88512e4 Move uses of to_bytes, to_text, to_native to use the module_utils version (#17423)
We couldn't copy to_unicode, to_bytes, to_str into module_utils because
of licensing.  So once created it we had two sets of functions that did
the same things but had different implementations.  To remedy that, this
change removes the ansible.utils.unicode versions of those functions.
8 years ago
Adrian Likins e396d5d508 Implement vault encrypted yaml variables. (#16274)
Make !vault-encrypted create a AnsibleVaultUnicode
yaml object that can be used as a regular string object.

This allows a playbook to include a encrypted vault
blob for the value of a yaml variable. A 'secret_password'
variable can have it's value encrypted instead of having
to vault encrypt an entire vars file.

Add __ENCRYPTED__ to the vault yaml types so
template.Template can treat it similar
to __UNSAFE__ flags.

vault.VaultLib api changes:
    - Split VaultLib.encrypt to encrypt and encrypt_bytestring

    - VaultLib.encrypt() previously accepted the plaintext data
      as either a byte string or a unicode string.
      Doing the right thing based on the input type would fail
      on py3 if given a arg of type 'bytes'. To simplify the
      API, vaultlib.encrypt() now assumes input plaintext is a
      py2 unicode or py3 str. It will encode to utf-8 then call
      the new encrypt_bytestring(). The new methods are less
      ambiguous.

    - moved VaultLib.is_encrypted logic to vault module scope
      and split to is_encrypted() and is_encrypted_file().

Add a test/unit/mock/yaml_helper.py
It has some helpers for testing parsing/yaml

Integration tests added as roles test_vault and test_vault_embedded
8 years ago
Toshio Kuratomi 7cb29cdbec Workaround py2.6's StringIO 9 years ago
Toshio Kuratomi b70bf3b056 Use io.StringIO and io.BytesIO instead of StringIO.StringIO for compat with py3 9 years ago
Matt Martz 2cd3a1be00 assertRaises should be given an exception type. Fixes 11441 10 years ago
James Cammarata ce3ef7f4c1 Making the switch to v2 10 years ago