Fix error when container has no names.

Rename loop variable from "i" to more informative "container"

Fixes #1188
reviewable/pr18780/r1
Toshio Kuratomi 10 years ago
parent a6eafb87c8
commit f444e49dfa

@ -1127,17 +1127,20 @@ class DockerManager(object):
else:
repo_tags = [normalize_image(self.module.params.get('image'))]
for i in self.client.containers(all=True):
for container in self.client.containers(all=True):
details = None
if name:
matches = name in i.get('Names', [])
name_list = container.get('Names')
if name_list is None:
name_list = []
matches = name in name_list
else:
details = self.client.inspect_container(i['Id'])
details = _docker_id_quirk(details)
running_image = normalize_image(details['Config']['Image'])
running_command = i['Command'].strip()
running_command = container['Command'].strip()
image_matches = running_image in repo_tags
@ -1149,7 +1152,7 @@ class DockerManager(object):
if matches:
if not details:
details = self.client.inspect_container(i['Id'])
details = self.client.inspect_container(container['Id'])
details = _docker_id_quirk(details)
deployed.append(details)

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