modify_module does not need to return module_path, as the calling code already has access to it

pull/13771/head
Matt Martz 8 years ago
parent 34adb54734
commit ca22783086

@ -739,7 +739,7 @@ def modify_module(module_name, module_path, module_args, task_vars=dict(), modul
(module_data, module_style, shebang) = _find_snippet_imports(module_name, module_data, module_path, module_args, task_vars, module_compression)
if module_style == 'binary':
return (module_path, module_data, module_style, shebang)
return (module_data, module_style, shebang)
elif shebang is None:
lines = module_data.split(b"\n", 1)
if lines[0].startswith(b"#!"):
@ -762,4 +762,4 @@ def modify_module(module_name, module_path, module_args, task_vars=dict(), modul
else:
shebang = to_bytes(shebang, errors='strict')
return (module_path, module_data, module_style, shebang)
return (module_data, module_style, shebang)

@ -145,7 +145,7 @@ class ActionBase(with_metaclass(ABCMeta, object)):
"run 'git submodule update --init --recursive' to correct this problem." % (module_name))
# insert shared code and arguments into the module
(module_path, module_data, module_style, module_shebang) = modify_module(module_name, module_path, module_args, task_vars=task_vars, module_compression=self._play_context.module_compression)
(module_data, module_style, module_shebang) = modify_module(module_name, module_path, module_args, task_vars=task_vars, module_compression=self._play_context.module_compression)
return (module_style, module_shebang, module_data, module_path)

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