Fixes #3129 Do not require localhost to be in inventory

pull/5693/head
James Tanner 11 years ago
parent c17d0e0357
commit 94f3b9bfab

@ -19,6 +19,7 @@
import fnmatch
import os
import sys
import re
import subprocess
@ -179,8 +180,9 @@ class Inventory(object):
elif p.startswith("&"):
hosts = [ h for h in hosts if h in that ]
else:
hosts.extend([ h for h in that if h.name not in [ y.name for y in hosts ] ])
to_append = [ h for h in that if h.name not in [ y.name for y in hosts ] ]
hosts.extend(to_append)
return hosts
def __get_hosts(self, pattern):
@ -264,6 +266,14 @@ class Inventory(object):
if host not in results and host.name not in hostnames:
results.append(host)
hostnames.add(host.name)
if pattern in ["localhost", "127.0.0.1"] and len(results) == 0:
new_host = Host(pattern)
new_host.set_variable("ansible_python_interpreter", sys.executable)
new_host.set_variable("ansible_connection", "local")
ungrouped = self.get_group("ungrouped")
ungrouped.add_host(new_host)
results.append(new_host)
return results
def clear_pattern_cache(self):
@ -356,7 +366,13 @@ class Inventory(object):
self._groups_list = None # invalidate internal cache
def list_hosts(self, pattern="all"):
return [ h.name for h in self.get_hosts(pattern) ]
""" return a list of hostnames for a pattern """
result = [ h.name for h in self.get_hosts(pattern) ]
if len(result) == 0 and pattern in ["localhost", "127.0.0.1"]:
result = [pattern]
return result
def list_groups(self):
return sorted([ g.name for g in self.groups ], key=lambda x: x)

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