Fix up to_datetime timedelta seconds docs (#82826)

pull/82850/head
Jordan Borean 2 months ago committed by GitHub
parent 732df49e46
commit 25c0dc50a2
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@ -4,9 +4,14 @@ DOCUMENTATION:
short_description: Get C(datetime) from string
description:
- Using the input string attempt to create a matching Python C(datetime) object.
- Adding or Subtracting two datetime objects will result in a Python C(timedelta) object.
notes:
- For a full list of format codes for working with Python date format strings, see
L(the Python documentation, https://docs.python.org/3/library/datetime.html#strftime-and-strptime-behavior).
- The timedelta object produced by the difference of two datetimes store the days, seconds, and microseconds of
the delta. This results in the C(seconds) attribute being the total seconds of the minutes and hours of that
delta. See L(datatime.timedelta, https://docs.python.org/3/library/datetime.html#timedelta-objects) for more
information about how a timedelta works.
positional: _input
options:
_input:
@ -22,9 +27,9 @@ EXAMPLES: |
# Get total amount of seconds between two dates. Default date format is %Y-%m-%d %H:%M:%S but you can pass your own format
secsdiff: '{{ (("2016-08-14 20:00:12" | to_datetime) - ("2015-12-25" | to_datetime("%Y-%m-%d"))).total_seconds() }}'
# Get remaining seconds after delta has been calculated. NOTE: This does NOT convert years, days, hours, and so on to seconds. For that, use total_seconds()
# Get remaining seconds after delta has been calculated. NOTE: This does NOT convert years and days to seconds. For that, use total_seconds()
{{ (("2016-08-14 20:00:12" | to_datetime) - ("2016-08-14 18:00:00" | to_datetime)).seconds }}
# This expression evaluates to "12" and not "132". Delta is 2 hours, 12 seconds
# This expression evaluates to "7212". Delta is 2 hours, 12 seconds
# get amount of days between two dates. This returns only number of days and discards remaining hours, minutes, and seconds
{{ (("2016-08-14 20:00:12" | to_datetime) - ("2015-12-25" | to_datetime('%Y-%m-%d'))).days }}

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