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Support multiple vault passwords (#22756)
Fixes #13243
** Add --vault-id to name/identify multiple vault passwords
Use --vault-id to indicate id and path/type
--vault-id=prompt # prompt for default vault id password
--vault-id=myorg@prompt # prompt for a vault_id named 'myorg'
--vault-id=a_password_file # load ./a_password_file for default id
--vault-id=myorg@a_password_file # load file for 'myorg' vault id
vault_id's are created implicitly for existing --vault-password-file
and --ask-vault-pass options.
Vault ids are just for UX purposes and bookkeeping. Only the vault
payload and the password bytestring is needed to decrypt a
vault blob.
Replace passing password around everywhere with
a VaultSecrets object.
If we specify a vault_id, mention that in password prompts
Specifying multiple -vault-password-files will
now try each until one works
** Rev vault format in a backwards compatible way
The 1.2 vault format adds the vault_id to the header line
of the vault text. This is backwards compatible with older
versions of ansible. Old versions will just ignore it and
treat it as the default (and only) vault id.
Note: only 2.4+ supports multiple vault passwords, so while
earlier ansible versions can read the vault-1.2 format, it
does not make them magically support multiple vault passwords.
use 1.1 format for 'default' vault_id
Vaulted items that need to include a vault_id will be
written in 1.2 format.
If we set a new DEFAULT_VAULT_IDENTITY, then the default will
use version 1.2
vault will only use a vault_id if one is specified. So if none
is specified and C.DEFAULT_VAULT_IDENTITY is 'default'
we use the old format.
** Changes/refactors needed to implement multiple vault passwords
raise exceptions on decrypt fail, check vault id early
split out parsing the vault plaintext envelope (with the
sha/original plaintext) to _split_plaintext_envelope()
some cli fixups for specifying multiple paths in
the unfrack_paths optparse callback
fix py3 dict.keys() 'dict_keys object is not indexable' error
pluralize cli.options.vault_password_file -> vault_password_files
pluralize cli.options.new_vault_password_file -> new_vault_password_files
pluralize cli.options.vault_id -> cli.options.vault_ids
** Add a config option (vault_id_match) to force vault id matching.
With 'vault_id_match=True' and an ansible
vault that provides a vault_id, then decryption will require
that a matching vault_id is required. (via
--vault-id=my_vault_id@password_file, for ex).
In other words, if the config option is true, then only
the vault secrets with matching vault ids are candidates for
decrypting a vault. If option is false (the default), then
all of the provided vault secrets will be selected.
If a user doesn't want all vault secrets to be tried to
decrypt any vault content, they can enable this option.
Note: The vault id used for the match is not encrypted or
cryptographically signed. It is just a label/id/nickname used
for referencing a specific vault secret.
7 years ago
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#!/usr/bin/env python
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#
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# Ansible is free software: you can redistribute it and/or modify
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# it under the terms of the GNU General Public License as published by
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# the Free Software Foundation, either version 3 of the License, or
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# (at your option) any later version.
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#
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# Ansible is distributed in the hope that it will be useful,
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# but WITHOUT ANY WARRANTY; without even the implied warranty of
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# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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# GNU General Public License for more details.
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#
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# You should have received a copy of the GNU General Public License
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# along with Ansible. If not, see <http://www.gnu.org/licenses/>.
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#
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# ansible-vault is a script that encrypts/decrypts YAML files. See
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# https://docs.ansible.com/ansible/latest/user_guide/vault.html for more details.
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Support multiple vault passwords (#22756)
Fixes #13243
** Add --vault-id to name/identify multiple vault passwords
Use --vault-id to indicate id and path/type
--vault-id=prompt # prompt for default vault id password
--vault-id=myorg@prompt # prompt for a vault_id named 'myorg'
--vault-id=a_password_file # load ./a_password_file for default id
--vault-id=myorg@a_password_file # load file for 'myorg' vault id
vault_id's are created implicitly for existing --vault-password-file
and --ask-vault-pass options.
Vault ids are just for UX purposes and bookkeeping. Only the vault
payload and the password bytestring is needed to decrypt a
vault blob.
Replace passing password around everywhere with
a VaultSecrets object.
If we specify a vault_id, mention that in password prompts
Specifying multiple -vault-password-files will
now try each until one works
** Rev vault format in a backwards compatible way
The 1.2 vault format adds the vault_id to the header line
of the vault text. This is backwards compatible with older
versions of ansible. Old versions will just ignore it and
treat it as the default (and only) vault id.
Note: only 2.4+ supports multiple vault passwords, so while
earlier ansible versions can read the vault-1.2 format, it
does not make them magically support multiple vault passwords.
use 1.1 format for 'default' vault_id
Vaulted items that need to include a vault_id will be
written in 1.2 format.
If we set a new DEFAULT_VAULT_IDENTITY, then the default will
use version 1.2
vault will only use a vault_id if one is specified. So if none
is specified and C.DEFAULT_VAULT_IDENTITY is 'default'
we use the old format.
** Changes/refactors needed to implement multiple vault passwords
raise exceptions on decrypt fail, check vault id early
split out parsing the vault plaintext envelope (with the
sha/original plaintext) to _split_plaintext_envelope()
some cli fixups for specifying multiple paths in
the unfrack_paths optparse callback
fix py3 dict.keys() 'dict_keys object is not indexable' error
pluralize cli.options.vault_password_file -> vault_password_files
pluralize cli.options.new_vault_password_file -> new_vault_password_files
pluralize cli.options.vault_id -> cli.options.vault_ids
** Add a config option (vault_id_match) to force vault id matching.
With 'vault_id_match=True' and an ansible
vault that provides a vault_id, then decryption will require
that a matching vault_id is required. (via
--vault-id=my_vault_id@password_file, for ex).
In other words, if the config option is true, then only
the vault secrets with matching vault ids are candidates for
decrypting a vault. If option is false (the default), then
all of the provided vault secrets will be selected.
If a user doesn't want all vault secrets to be tried to
decrypt any vault content, they can enable this option.
Note: The vault id used for the match is not encrypted or
cryptographically signed. It is just a label/id/nickname used
for referencing a specific vault secret.
7 years ago
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from __future__ import (absolute_import, division, print_function)
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__metaclass__ = type
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import sys
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PASSWORD = 'test-vault-password'
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def main(args):
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print(PASSWORD)
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return 0
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if __name__ == '__main__':
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sys.exit(main(sys.argv[:]))
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